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02-07-07, 05:16
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#1 (permalink)
| | Registered User
BMW335i is offline
Join Date: Oct 2006 Location: Long Island, NY Posts: 1,020 | Help with Calculus? Can anyone solve this for me in y=mx+b form?
- Find the equations of the tangent lines at the points (1,5) and (2,3).
How you got the answer would be greatly appreciated.
P.S. I feel pretty silly asking a detailing forum about this but I know alot of you guys are smart so its worth a shot
function is y = 3 + 4x^2 - 2x^3 | |
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02-07-07, 05:29
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#2 (permalink)
| | Not too old to learn.
RTexasF is offline
Join Date: Apr 2005 Location: Brownsville TX Posts: 771 | Re: Help with Calculus? I feel for you, honestly. I'm one of those that could not comprehend Jr. High algebra......with a brilliant tutor. Sorry I can't be of help. | |
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02-07-07, 05:50
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#3 (permalink)
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Sergei is offline
Join Date: Oct 2006 Posts: 167 | Re: Help with Calculus? Giving you the answer will be cheating. :-)
Go to this link for an explanation of the y=mx+b form (which is the slope intercept form). Straight-Line Equations: Slope-Intercept Form
Walk through the example that is given. If you understand that example, you can derive your answer as posed above. | |
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02-07-07, 05:52
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#4 (permalink)
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BMW335i is offline
Join Date: Oct 2006 Location: Long Island, NY Posts: 1,020 | Re: Help with Calculus? Alright well I asked my bro and he explained it to me. Thanks anyway guys! | |
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02-07-07, 07:35
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#5 (permalink)
| | Vee-dub in da hauz, yah
Sherman8r44 is offline
Join Date: Sep 2005 Location: Lawng Oiland, New Yawk Posts: 1,065 | Re: Help with Calculus? Just in case you're still unclear or anyone else needs to know...here are the steps:
1. Differentiate the function. The derivative will be the slope ("m") of the y=mx+b form, because derivatives are, by definition, the slope of the tangent line.
2. Assuming you're doing this in point-slope form, take the coordinates (in this case first (1,5)) and plug it into the form so that the result is (y-5)=m(x-1), which then you should be able to simplify to get a resulting y=mx+b equation. | |
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02-07-07, 08:30
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#6 (permalink)
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MorBid is offline
Join Date: Nov 2004 Location: Rochester, NY Posts: 1,312 | Re: Help with Calculus? y=mx+b is the equation for finding the slope of a line (as mentioned).
That's Algebra not Calculus.
MorBiD | |
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02-07-07, 09:31
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#7 (permalink)
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Sergei is offline
Join Date: Oct 2006 Posts: 167 | Re: Help with Calculus? Yep, it's algebra... linear equation by plotting the y-intercept, and plotting another point by using the slope of the line. It could be a course that leads you into Calculus with a little warm-up from Algebra.
Wait a minute... this is a detailing forum. I'm here to de-stress. If anything, we should be discussing chemistry. Like what is the cross-linking molecular structure of polymers vs. simple carnuba wax? | |
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02-07-07, 09:59
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#8 (permalink)
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MorBid is offline
Join Date: Nov 2004 Location: Rochester, NY Posts: 1,312 | Re: Help with Calculus? You know, there are threads here that discuss that very topic. But at university my majors required lots of math and no chemistry so I stay out of it  | |
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02-08-07, 07:44
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#9 (permalink)
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DFTowel is offline
Join Date: Aug 2002 Location: LI, NY Posts: 1,043 | Re: Help with Calculus? I could tell you the answer but I'd have to kill you afterwards. | |
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02-08-07, 04:53
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#10 (permalink)
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tyymm is offline
Join Date: Jul 2002 Location: Greenville, SC Posts: 81 | Re: Help with Calculus? If you still can't get it let me know... I will be checking this post for an hour, if you need it I will give you my cell phone number and I will talk you through the equation/calculations.
Math is one of those things that when you see the path you never forget it. If you don't see the path, then no map in the world can help. | |
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02-08-07, 06:15
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#11 (permalink)
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BMW335i is offline
Join Date: Oct 2006 Location: Long Island, NY Posts: 1,020 | Re: Help with Calculus? Quote: |
Originally Posted by tyymm If you still can't get it let me know... I will be checking this post for an hour, if you need it I will give you my cell phone number and I will talk you through the equation/calculations.
Math is one of those things that when you see the path you never forget it. If you don't see the path, then no map in the world can help. | Thanks for the generous offer, but I got the answer (turned out to be pretty simple). I really appreciate you wanting to help!
BTW - to the previous posters, this is Calculus, you need limits to solve the problem. | |
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02-08-07, 08:21
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#12 (permalink)
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paul34 is offline
Join Date: Sep 2006 Location: Orlando, FL (UCF) Posts: 1,148 | Re: Help with Calculus? limits? Hum, have you all learned differentiation yet? It'll get a lot easier after that. You won't have to worry about that long formula with limits and all.
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